Question 12

If the electronic configuration of an element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2} 4 s^{2}$ the four electrons involved in chemical bond formation will be

(a) $3 p^{6}$

(b) $3 p^{6}, 4 s^{2}$

(c) $3 p^{6}, 3 d^{2}$

(d) $3 d^{2}, 4 s^{2}$

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Solution

Answer: (d) $3 d^{2}, 4 s^{2}$

The d block elements have multiple valencies. The given electronic configuration shows that an element is Vanadium (Z = 22). It belongs to d-block of the periodic table. In transition elements i.e., d-block elements, electrons of $n s a n d (n - 1) d$ subshell take part in bond formation.

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Q. If the electronic configuration of an element is

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2} 4 s^{2}

, the four electrons involved in chemical bond formation will be:

Question 21
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Question 12 If the electronic configuration of an element is 1s2 2s2 2p6 3s2 3p6 3d2 4s2 the four electrons involved in chemical bond formation will be (a) 3p6 (b) 3p6, 4s2 (c) 3p6, 3d2 (d) 3d2, 4s2

Question 12

If the electronic configuration of an element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2} 4 s^{2}$ the four electrons involved in chemical bond formation will be

(a) $3 p^{6}$

(b) $3 p^{6}, 4 s^{2}$

(c) $3 p^{6}, 3 d^{2}$

(d) $3 d^{2}, 4 s^{2}$