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Question

If the electronic configuration of nitrogen had 1s7, it would have energy lower than that of the normal ground state configuration 1s22s22p3 because the electrons would be closer to the nucleus. Yet 1s7 is not observed because it violates:

A
Heisenberg uncertainty principle
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B
Hund's rule
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C
Pauli's exclusion principle
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D
Bohr postulates of stationary orbits
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Solution

The correct option is B Pauli's exclusion principle
1s7 is not observed because it violates Pauli's exclusion principle which states that "two electrons in an atom cannot have the same set of all four quantum numbers". In other words, "only two electrons may exist in the same orbital with three quantum numbers same i.e the fourth quantum number different and these electrons have opposite spin."

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