If the empirical formula of the compound is CH and it has a bakery density of 13 find the molecular formula of the compound

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Solution

I think it is vapour density instead of bakery density
Vapor density = 1/2 Molecular Mass
Molecular mass = vapour density×2=26g
Molecular mass = 13×2=26g

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If the empirical formula of the compound is CH and it has a bakery density of 13 find the molecular formula of the compound

I think it is vapour density instead of bakery density Vapor density = 1/2 Molecular Mass Molecular mass = vapour density×2=26g Molecular mass = 13×2=26g

I think it is vapour density instead of bakery density
Vapor density = 1/2 Molecular Mass
Molecular mass = vapour density×2=26g
Molecular mass = 13×2=26g