If the empirical formula of two compounds is CH and their vapour densities are 13 and 39 respectively, find their molecular formula.

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Solution

Ans: Molecular mass = 2 $\times$ vapour density
Given vapour density of x =13
Molecular mass = 2 $\times$ 13
= 26
The organic compound containing Carbon and Hydrogen with molecular weight - 26 (x) is $C_{2} H_{2}$ (Acetylene).
Given vapour density of y = 39
Molecular mass = 2 $\times$ 39
= 78
The organic compound containing Carbon and Hydrogen with molecular weight - 78 (y) is $C_{6} H_{6}$ (Benzene).

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