Question

If the energy of electron in H atom is given by expression $-\frac{1312}{n^2}$ kJ mol${}^{-1}$, then the energy required to excite the electron from ground state to second orbit is :

• A. 328 kJ
• B. 656 kJ
• C. 984 kJ
• D. 1312 kJ

Answer 1

Answer: (C)

984 kJ

$-\frac{1312}{2^2}+\frac{1312}{1^2}=984kJ$