Question

If the energy released in the fission of one nucleus is 200 MeV, then the number of nuclei required per second in a power plant of 16 kW will be:

• A. $0.5\times {10}^{14}$
• B. $0.5\times {10}^{22}$
• C. $5\times {10}^{12}$
• D. $5\times {10}^{14}$

Answer 1

The correct option is D $5\times {10}^{14}$

According to the question,

Released energy in fission of one nucleus $=200MeV$

$=200\times {10}^6\times 1.6\times {10}^{-19}J$

$=3.2\times {10}^{-11}J$

$P=16KW$

$=16\times {10}^{3}watt$

So, the number of required $nuclei/second$ is

$n=\frac{P}{E}=\frac{16\times {10}^3}{3.2\times {10}^{-11}}$

$=5\times {10}^{14}$