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Question

If the energy stored in spring A=10 J, then energy stored in B is (under same stretching force)

A
10 J
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B
5 J
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C
2.5 J
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D
1.25 J
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Solution

The correct option is B 5 J
It is given that, energy stored in the spring A is EA=12kx2A, (xA=FK)

Energy stored in spring (EB)=12(Kspring,B)×(x2B) where Kspring,B=2K
xB=(F2K)
EB=12×2K×(F2K)2=12×(12×K×(FK)2)
(EA)=(12×K×(FK)2)
EB=12×(EA)=12×10 J
EB=5 J

Hence option B is the correct answer.

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