The correct option is B 5 J
It is given that, energy stored in the spring A is EA=12kx2A, (xA=FK)
Energy stored in spring (EB)=12(Kspring,B)×(x2B) where Kspring,B=2K
xB=(F2K)
∴EB=12×2K×(F2K)2=12×(12×K×(FK)2)
∵(EA)=(12×K×(FK)2)
⇒EB=12×(EA)=12×10 J
⇒EB=5 J
Hence option B is the correct answer.