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Question

If the energy stored in spring 'A' is 20 J, then energy stored in spring 'B' is (under the same stretching force)


A
10 J
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B
25 J
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C
40 J
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D
35 J
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Solution

The correct option is C 40 J
Let EA= Energy stored in spring A
EB= Energy stored in spring B
xA= Displacement of spring A
xB= Displacement of spring B

Then, EB=12kx2B=12k×(Fk)2
=F22k ... (i)
& EA=12×2k×x2A=12×2k×(F2k)2
=F24k ... (ii)

Dividing (i) by (ii):
EBEA=F22KF24K=2
EB20=2EB=40 J

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