If the equation ax2 + (2 – b) xy + 3y2 – 6bx + 30y + 6b = 0 represents a circle, then a = __________, b = __________.
Open in App
Solution
Since ax2 + (2 – b) xy + 3y2 – 6bx + 30y + 6b = 0 represent circle ⇒ 2 – b = 0 (∵ xy term has coefficient equal to zero always)
i.e. b = 2
and a = 3 (∵ coefficient of x2 = coeffcient of y2 in case of circle)