Question

If the equation $\frac{\lambda {(x+1)}^2}{3}+\frac{{(y+2)}^2}{4}=1$ represents a circle then $\lambda =$

• A. $1$
• B. $\frac{3}{4}$
• C. $0$
• D. $-\frac{3}{4}$

Answer 1

Answer: (B)

$\frac{3}{4}$

in a circle$x^2,y^2$ coefficients must be same [it is the condition for the equation to be circle]

therefore

$\frac{\lambda }{3}=\frac{1}{4}$

$\Rightarrow \lambda =\frac{3}{4}$

option B