If the equation for the angular displacement of a particle moving on a circular path is given by θ=2t3+0.5, where θ is in radians and t in seconds, then the angular velocity of the particle at 2s is
A
8rad/s
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B
12rad/s
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C
24rad/s
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D
36rad/s
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Solution
The correct option is C24rad/s Given that θ=2t3+0.5 We know that, Angular velocity ω=dθdt Therefore, at t=2s. ω=6t2=6×(2)2=24rad/s Hence, the correct answer is option (c).