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Question

If the equation for the angular displacement of a particle moving on a circular path is given by θ=2t3+0.5, where θ is in radians and t in seconds, then the angular velocity of the particle at 2 s is

A
8 rad/s
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B
12 rad/s
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C
24 rad/s
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D
36 rad/s
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Solution

The correct option is C 24 rad/s
Given that θ=2t3+0.5
We know that,
Angular velocity ω=dθdt
Therefore, at t=2 s.
ω=6t2=6×(2)2=24 rad/s
Hence, the correct answer is option (c).

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