Question

If the equation for the displacement of a particle moving on a circular path is given as $\theta =2t^3+0.5$ where $\theta$ is in radians and t is in second. Then the angular velocity of the particle after two second will be:

• A. $36rad/sec$
• B. $8rad/sec$
• C. $48rad/sec$
• D. $24rad/sec$

Answer 1

The correct option is D $24rad/sec$

$\theta =2t^3+0.5$
$\omega =\frac{d\theta }{dt}=6t^2=6\times 2^2$
$=6\times 4=24radian/sec$