Question

if the equation kx^2+2kx+6=0 has equal roots then find the value of k.

Answer 1

Given equation: kx²-2kx+6=0

the basic form of any quadratic equation is:

ax²+bx+c=0.

So: a=k, b=-2k, c=6.

for any equation having equal roots,

b²-4ac=0, or b²=4ac;

Therefore 4k² = 24k

4k² - 24k = 0

Dividing throughout by 4, we get

k² - 6k =0

Taking k common k(k-6)=0

Therefore k can be either 6 or 0

k = 6 , 0