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Question

If the equation (logax)2loga(|x|)2=3 has repeated solution, then possible number of real values of a is

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Solution

(logax)2loga(|x|)2=3
Clearly, x>0
Then, (logax)22logax3=0 [x>0]
(logax3)(logax+1)=0
x=a3 (or) x=a1
For repeated solution,
a3=a1a=±1
But neither value of a satisfies the given equation.
No value of a gives repeated solution for the given equation.

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