(logax)2−loga(|x|)2=3
Clearly, x>0
Then, (logax)2−2logax−3=0 [∵x>0]
⇒(logax−3)(logax+1)=0
⇒x=a3 (or) x=a−1
For repeated solution,
a3=a−1⇒a=±1
But neither value of a satisfies the given equation.
∴ No value of a gives repeated solution for the given equation.