If the equation of line parallel to the line $3 x - 4 y + 2 = 0$ and passing through the point $(- 2, 3)$ is $3 x - 4 y + k,$ value of $k$ is

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Solution

Equation of line parallel to $3 x - 4 y + 2 = 0$ is
given by, $3 x - 4 y + k = 0$
Given it also passes through $(- 2, 3)$
$\Rightarrow 3 (- 2) - 4 (3) + k = 0 \Rightarrow k = 18$
Thus equation of required line is, $3 x - 4 y + 18 = 0$

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If the equation of line parallel to the line 3x−4y+2=0 and passing through the point (−2,3) is 3x−4y+k, value of k is

Equation of line parallel to 3x−4y+2=0 isgiven by, 3x−4y+k=0Given it also passes through (−2,3)⇒3(−2)−4(3)+k=0⇒k=18Thus equation of required line is, 3x−4y+18=0

If the equation of line parallel to the line $3 x - 4 y + 2 = 0$ and passing through the point $(- 2, 3)$ is $3 x - 4 y + k,$ value of $k$ is

Equation of line parallel to $3 x - 4 y + 2 = 0$ is
given by, $3 x - 4 y + k = 0$
Given it also passes through $(- 2, 3)$
$\Rightarrow 3 (- 2) - 4 (3) + k = 0 \Rightarrow k = 18$
Thus equation of required line is, $3 x - 4 y + 18 = 0$