Question

If the equation $sin\theta =-\frac{1}{2}andtan\theta =\frac{1}{\sqrt{3}}$ then the most common general values of $\theta$ is

• A.
• B.
• C.
• D. 2nπ+π/2

Answer 1

The correct option is C

$sin\theta =\frac{-1}{2}\Rightarrow \theta =\frac{7\pi }{6}or\frac{11\pi }{6}$[ $\because$ values between 0 and $2\pi$]

$tan\theta =\frac{1}{\sqrt{3}}\Rightarrow \theta =\frac{\pi }{6}or\frac{7\pi }{6}$

The required solution is $\theta =2n\pi +\frac{7\pi }{6}$