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Question

If the equation (x+5)2+(y+2)2=λ(x+3y+3) represent a parabola, then 1λ=

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Solution

The given equation is
(x+5)2+(y+2)2=λ(x+3y+3)(x+5)2+(y+2)2=2λ(x+3y+3)12+32
Now for parabola
2λ=1λ=14

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