CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the equation x2+2(k+2)x+9k=0 has equal roots, then values of k are __________.


A

1 or 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

–1 or 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1 or –5

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

–1 or –4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

1 or 4


Step 1:- For, x2+2(k+2)x+9k=0, value of discriminant D=[2(k+2)]24(9k)=4(k2+45k)

Step 2:- The roots of quadratic equation are real and equal only when D=0
k2+45k=0
k25k+4=0
k2k4k+4=0
k(k1)4(k1)=0
(k1)(k4)=0

Step 3:- k=4 or 1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon