Question

If the equation $x^2-bx+1=0$ does not possess real roots, then :

• A. -3 < b < 3
• B. -2 < b < 2
• C. b > 2
• D. b < -2

Answer 1

The correct option is B -2 < b < 2

Since the equation does not possess real roots, then D < 0
$\therefore b^2-4<0$
$\Rightarrow (b-2)(b+2)<0$
$\Rightarrow -2<b<2$