If the equation x2−px+216=0 has one root as a square of the other, find the value of p
42
−30
36
30
x2−px+216=0 Let the roots of the equation be α,α2. Product of roots =ca=α×α2 ⇒α3=216 ⇒α=6 Sum of roots =−ba=α+α2=p1 ⇒6+36=p ⇒p=42
The equation x2+px−q=0 has one root as a square root of the other. If p3+q2=q(1+kp), find the value of k.
For the equation 3x2+px+3=0,p>0, if one of the roots is the square of the other, then find the value of p.