If the equation x5−10a3x2+b4x+c5=0has 3 equals roots, then
A
2b2−10a3b2+c5=0
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B
6a5+c5=0
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C
2c5−10a3b2+b4c5=0
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D
b4=15a4
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Solution
The correct options are B6a5+c5=0 Db4=15a4 f(x)=x5−10a3x2+b4x+c5 f′(x)=5x4−20a3−20a3x+b4 f′′=20x3−20a3 If x=α be a root that is repeated 3 times, then f′′(α)=0 and f(α)=0 ⇒α=a,5a4−20a4+b4=0 a5−10a5+ab4+c5=0 ⇒α=a,b4=15a4 and 6a5+c5=0