If the equations 2x2+3x+5λ=0 and x2+3x+3λ=0 have a common root, then λ is equal to
A
0,−18
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B
−1
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C
0,−1
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D
2,−1
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Solution
The correct option is A0,−18 Let α be the common root. Therefore, 2(α)2+3α+5λ=0...(i) (α)2+3α+3λ=0...(ii) Subtracting (ii) from (i), we get α2+2λ=0 α=±√−2λ Substituting in 2x2+3x+5λ=0 we get 2(−2λ)±3(√−2λ)+5λ=0