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Question

If the equations k(6x2+3)+rx+(2x21)=0 and 6k(2x2+1)+px+(4x22)=0,k0 have both roots common, then the value of pr is

A
2
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B
12
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C
1
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D
4
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Solution

The correct option is A 2
(6k+2)x2+rx+3k1=0 (1)
(12k+4)x2+px+6k2=0 (2)
Since the roots of eqns. (1) and (2) are equal,
6k+212k+4=rp=3k16k2pr=2

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