If the equations of four circles are x - 42-y - 42-42 then the radius of the smallest circle touching all the four circles is

The correct option is B OB = 4 √(2) 0A + AB = 4 √(2) 4 + AB = 4 √(2) AB = 4 √(2) 4 ...

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If the equati...

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If the equations of four circles are $(x \pm 4)^{2} + (y \pm 4)^{2} = 4^{2}$ then the radius of the smallest circle touching all the four circles is

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{(x \pm 4)}^{2} + {(y \pm 4)}^{2} = 4^{2}

The equations of four circles are $(x \pm a)^{2} + (y \pm a)^{2} = a^{2}$ . The radius of a circle touching all four circles is

(x \pm a)^{2} + (y \pm a)^{2} = a^{2}

(x \pm 5)^{2} + (y \pm 5)^{2} = 25.

(x + 1)^{2} + (y - 4)^{2} = 16

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