The correct option is A 1 : 2 : 3
Given equations are x2+2x+3=0 ......(i)
And ax2+bx+c=0 ....(ii)
Since, Eq. (i) has imaginary roots, so Eq. (ii) will also have both roots same as Eq. (i), (because imaginary roots always occur in pair. If one root is a+ib, then other is a-ib.)
Thus, a1=b2=c3
Hence, a : b : c is 1 : 2 : 3