If the equilibrium constant for N 2 g - O 2 g - 2 NO g is K- the equilibrium constant for 1-2 N 2 g -1-2 O 2 g - NO g will be-A- K 1 - 2S- 1-2 KC- K D- K 2

The correct option is A K^1/2N_2(g)+O_2(g)⇌ 2NO(g) K=[NO]^2[N_2][O_2] ......(1) 12N_2(g)+12O_2(g)⇌ NO(g) K'=NO[N_2]^1/2[O_2]^1/2 .....(2) Compairing equa ...

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Byju's Answer

Standard XII

Chemistry

Effect on Kc

If the equili...

Question

If the equilibrium constant for $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$ is $K$ , the equilibrium constant for $\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$ will be:

K^{1 / 2}

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\frac{1}{2} K

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K

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K^{2}

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Solution

The correct option is A $K^{1 / 2}$
$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$
$K = \frac{[N O]^{2}}{[N_{2}] [O_{2}]} . . . . . . (1)$
$\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$
$K^{'} = \frac{N O}{[N_{2}]^{1 / 2} [O_{2}]^{1 / 2}} . . . . . (2)$
Compairing equation $(1) a n d (2)$ , we get
$∴ K^{'} = \sqrt{K}$

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Similar questions

Q. If the equilibrium constant for

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

K

, the equilibrium constant for

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)

will be :-

Q. If the equilibrium constant for

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

K

, the equilibrium constant for

\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)

will be:

K_{1}

and

K_{2}

are equilibrium constant for reactions (1) & (2)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g)

Then :

K_{1}

and

K_{2}

are equilibrium constants for reaction (i) and (ii)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

.....(i)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g)

.....(ii)
Then :

K_{1}

and

K_{2}

are equilibrium constant for reactions (1) and (2)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g) . . . . . . (1)

N O (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) . . . . . . . . . (2)

Then,

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If the equilibrium constant for N2(g)+O2(g)⇌2NO(g) is K, the equilibrium constant for 12N2(g)+12O2(g)⇌NO(g) will be:

The correct option is A K1/2N2(g)+O2(g)⇌2NO(g) K=[NO]2[N2][O2] ......(1) 12N2(g)+12O2(g)⇌NO(g) K′=NO[N2]1/2[O2]1/2 .....(2) Compairing equation (1) and (2), we get ∴K′=√K

If the equilibrium constant for $N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$ is $K$ , the equilibrium constant for $\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ N O (g)$ will be: