Question

If the Euler load for a steel column is $1000kN$ and crushing load is $1500kN$, the Rankine load is equal to

• A. $2500kN$
• B. $1500kN$
• C. $1000kN$
• D. $600kN$

Answer 1

The correct option is D $600kN$

Rankine load is given by
$\frac{1}{P}=\frac{1}{P_E}+\frac{1}{P_C}$
$\Rightarrow P=\frac{P_E{P}_C}{P_E+P_C}$
$\Rightarrow P=\frac{1000\times 1500}{100+1500}$
$\Rightarrow P=600kN$