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Question

# If the excess pressure inside a soap bubble of radius 1 cm is balanced by an oil (ρ=0.8 g/cm3) column of height 2 mm, then the surface tension of soap solution will be [Take g=10 m/s2]

A
0.02 N/m
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B
0.04 N/m
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C
0.09 N/m
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D
0.08 N/m
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Solution

## The correct option is B 0.04 N/mGiven, Radius of soap bubble, R=1 cm=10−2 m Density of oil, ρ=0.8 g/cm3=800 kg/m3 Height of oil column, h=2 mm=2×10−3 m Let us suppose, surface tension of soap solution is T. We know that, excess pressure inside soap bubble is given by ΔP=4TR =4T10−2=400T .......(1) Pressure due to height of oil column, P=ρgh =800×10×2×10−3 =16 N/m2 ..........(2) Given, pressure due to height of oil column is equal to excess pressure of soap bubble. From (1) and (2) 400T=16 ⇒T=0.04 N/m

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