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Question

If the expansion (x2+1x3)n is to contain an independent term, then what should be the value of n?

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Solution

General term, Tr+1=nCrxnryr, for (x+y)n
general term of (x2+1x3)n is
nCrx2n2r1x3r=nCrx2n5r
For a term to be independent of x, 2n5r should be equal to zero.
r=25n, since r can take only integral values, n has to be a multiple.of 5.

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