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Question

If the expression (a−2)x2+2(2a−3)x+(5a−6) is positive for all real values of x, then

A
a can be any real number
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B
a>1
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C
a>3
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D
a=3
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Solution

The correct option is C a>3
The expression is always positive that means the discriminant of the equation is always less than zero .
So, 4(2a3)24(a2)(5a6)<0
(16a2+3648a)(20a264a+48)<0
(4a2+16a12)<0
(4)(a24a+3)<0
(a3)(a1)>0
So, the expression will be positive for a>3 and a<1
Option C is correct .

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