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Question

If the expression 2i52i is reduced to (a+bi), where a,b are real numbers, then the value of b is

A
129
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B
129
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C
29
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D
29
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Solution

The correct option is A 129
The value of 2i52i
=2i52i×5+2i5+2i
=(2i)(5+2i)(52i)(5+2i)
=10+4i5i+225+4
=12i29
=1229i29
After comparing this with a+ib, we get
a=1229,b=129
b=129

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