If the expression sinx/2+cosx/2−itanx1+2isinx/2 is real, then the set of all possible values of x is ...................
A
nπ/4
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B
nπ/2
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C
nπ
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D
2nπ
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Solution
The correct option is D2nπ The above expression will be real if imaginary part is 0. Thus tan(x)=0 x=nπ ...(i) And sin(x2)=0 x2=nπ x=2nπ ...(ii) Hence From i and ii, we get the solution as 2nπ. where nϵN