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Question

If the expression sinx/2+cosx/2itanx1+2isinx/2 is real, then the set of all possible values of x is ...................

A
nπ/4
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B
nπ/2
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C
nπ
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D
2nπ
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Solution

The correct option is D 2nπ
The above expression will be real if imaginary part is 0.
Thus
tan(x)=0
x=nπ ...(i)
And
sin(x2)=0
x2=nπ
x=2nπ ...(ii)
Hence
From i and ii, we get the solution as 2nπ. where nϵN

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