If the expression f(x)=x2+6x+k is non negative ∀x∈R, then the interval in which k lies is
A
(−∞,∞)
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B
(9,∞)
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C
[9,∞)
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D
(−∞,9)
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Solution
The correct option is C[9,∞) f(x)=x2+6x+k, a=1, b=6, c=k
As f(x) is always ≥0, so graph touches or lies above the x−axis.
Hence, D≤0 ⇒b2−4ac≤0 ⇒36−4k≤0 ⇒4k−36≥0 ⇒k≥9⇒k∈[9,∞)