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Question

If the expression f(x)=x2+6x+k is non negative xR, then the interval in which k lies is

A
(,)
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B
(9,)
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C
[9,)
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D
(,9)
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Solution

The correct option is C [9,)
f(x)=x2+6x+k,
a=1, b=6, c=k
As f(x) is always 0, so graph touches or lies above the xaxis.
Hence, D0
b24ac0
364k0
4k360
k9k[9,)

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