If the extremities of a diagonal of a square are (1,−2,3) and (2,−3,5), then the length of its side (in units) is:
A
√6
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B
√3
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C
√5
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D
√7
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Solution
The correct option is B√3 Let s be the side and d be the diagonal of a square respectively.
Hence s=d√2⋯(i)
Let A(1,−2,3) and C(2,−3,5) be the extremities of the diagonal AC
The length of diagonal d=√(x2−x1)2+(y2−y1)2+(z2−z1)2 d=√(2−1)2+(−3+2)2+(5−3)2 d=√1+1+4 d=√6
From equation (i) s=d√2=√6√2=√3
Length of side =√3 units