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Question

If the fifth term in the expansion of (x1/3+1x)n
does not depend upon x, then nC2+nC14 equals

A
240
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B
480
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C
360
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D
120
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Solution

The correct option is A 240
Given expansion is (x13+1x)n
The general term is nCrxnr3xr
Given fifth term is independent of x,
r=4,
Subtituting the value of r in the general term gives,
t5=nC4xn163
Given that this value is independent of x
n=16
the required value is 16C2+16C142(16C2)240
formula used is nCr=nCnr

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