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Question

If the first and (2n+1)th terms of an A.P, G.P, and H.P. are equal and their (n+1)th terms are a, b and c respectively, then

A
a>b>c
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B
ac=b2
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C
a+b=c
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D
none of these
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Solution

The correct option is A ac=b2
Let A be the first term,

D be the common difference

and B be the (2n+1)th term of the A.P.

then B=A+2nDD=BA2n

Also, a=A+(n+11)=A+B2

Similarly, b=AB and c=2ABA+B

Clearly, we have b2=ac

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