If the first term of an AP is -8 and the common difference is 4, then the sum of the first ten terms is

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100

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104

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Solution

The correct option is C 100
$S_{n} = \frac{n}{2} [2 a + (n - 1) d] S_{10} = \frac{10}{2} (2 (- 8) + 9 (4)) S_{10} = 100$

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If the first term of an AP is -8 and the common difference is 4, then the sum of the first ten terms is

The correct option is C 100Sn=n2[2a+(n−1)d]S10=102(2(−8)+9(4))S10=100

The correct option is C 100
$S_{n} = \frac{n}{2} [2 a + (n - 1) d] S_{10} = \frac{10}{2} (2 (- 8) + 9 (4)) S_{10} = 100$