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Question

If the first term of an AP is -8 and the common difference is 4, then the sum of the first ten terms is
  1. 100
  2. 104
  3. 92
  4. 96


Solution

The correct option is A 100
Sn=n2[2a+(n1)d]S10=102(2(8)+9(4))S10=100

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