If the flow of water in the tank stops, what will be the depth of water in the tank. Assume that the level of oil outside the tank does not increase.

30 cm

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10 cm

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2 cm

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None of these

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Solution

The correct option is D
None of these

So for the water to stop flowing, Pressure from both sides should be the same.

$P_{1} = P_{0} + ρ o g (h_{1} + h_{2}) = P_{0} + ρ_{0} g (15)$
$P_{2} = P_{0} + ρ o g h_{1} + g h_{2 ρ w}$
$i s g i v e n h_{1} = 5 c m$
$F o r P_{1} = P_{2}$
$P_{0} + ρ o g (15) = P_{0} + ρ o g (5) + g h_{2 ρ w}$
$ρ_{0} (10) = ρ_{w} h_{2}$
$h_{2} = \frac{ρ 0}{ρ w} (10) = 0.8 \times 10 = 8 c m$

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If the flow of water in the tank stops, what will be the depth of water in the tank. Assume that the level of oil outside the tank does not increase.

The correct option is D None of these So for the water to stop flowing, Pressure from both sides should be the same. P1=P0+ρog(h1+h2)=P0+ρ0g(15) P2=P0+ρogh1+gh2ρw isgivenh1=5cm ForP1=P2 P0+ρog(15)=P0+ρog(5)+gh2ρw ρ0(10)=ρwh2 h2=ρ0ρw(10)=0.8×10=8cm