If the flow rate of water from a pipe is $2 m^{3} s^{- 1}$ , then how much time will it take to fill a bucket of volume $1200 m^{3}$ ?

8 min

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9 min

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10 min

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12 min

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Solution

The correct option is A
8 min

Time taken to fill the bucket = $\frac{Volume of the bucket}{Flow rate of water}$
= $\frac{1200 m^{3}}{2 \frac{m^{3}}{s}}$
= $600 s$
= $10$ minutes

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Similar questions

If the rate of flow of water from a pipe is $2 m^{3} s^{- 1}$ , then how much time will it take to fill a bucket whose volume is $1200 m^{3}$ ?

If the flow rate of water from a pipe is $2 m^{3} / s$ , then how much time it will take to fill a bucket of volume $1200 m^{3}$ ?

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