If the focal lengths of objective and eye lens of a microscope are 1.2 cm and 3 cm respectively and the object is put 1.25 cm away from the objective lens and the final image is formed at infinity, then magnifying power of the microscope is

150

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200

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250

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400

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Solution

The correct option is B 200
Given that $f_{0} = 1.2 c m, f_{e} = 3 c m, u_{0} = 1.25 c m$
By using $m_{\infty} = - \frac{f_{0}}{(u_{0} - f_{0})} . \frac{D}{f_{e}} \Rightarrow= - \frac{1.2}{(1.25 - 1.2)} \times \frac{25}{3} = - 200$

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If the focal lengths of objective and eye lens of a microscope are 1.2 cm and 3 cm respectively and the object is put 1.25 cm away from the objective lens and the final image is formed at infinity, then magnifying power of the microscope is

The correct option is B 200Given that f0=1.2cm,fe=3cm,u0=1.25cm By using m∞=−f0(u0−f0).Dfe⇒=−1.2(1.25−1.2)×253=−200

The correct option is B 200
Given that $f_{0} = 1.2 c m, f_{e} = 3 c m, u_{0} = 1.25 c m$
By using $m_{\infty} = - \frac{f_{0}}{(u_{0} - f_{0})} . \frac{D}{f_{e}} \Rightarrow= - \frac{1.2}{(1.25 - 1.2)} \times \frac{25}{3} = - 200$