If the focus of parabola is at (0,−3) and its directrix is y=3, then its equation is:
A
x2=−12y
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B
x2=12y
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C
y2=−12y
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D
y2=12x
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Solution
The correct option is Ax2=−12y Given, focus =(0,−3) and its direction y=3
P is any point on the parabola and S is the focus and M is on the the Directrix such that PM is perpendicular to directrix. Using definition of parabola PS=PM⇒PS2=PM2