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Question

If the following functions have both domain and co-domain as [1,1], then select those which are not bijective?

A
sin(sin1x)
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B
2πsin(sin1x)
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C
sgn(x)ln(ex)
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D
sgn(x)x3
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Solution

The correct option is D sgn(x)x3
f(x)=sin(sin1x)=x x[1,1], which is one-one and onto.
f(x)=2πsin(sin1x)=2πx
The range of the function for x[1,1] is [2π,2π], which is a subset of [1,1].
Hence, the function is one-one but not onto and, hence, is not bijective.

f(x)=sgn (x)ln(ex)=(sgn (x))x={x, x>0 x, x<0 0, x=0

This function has range [0,1] which is a subset of [1,1].
Hence, the function is into. Also, the function is many-one.

f(x)=x3sgn (x)=x3, x>0 x3, x<0 0, x=0
which is many-one and into.

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