Question

If the following ion is coloured enter 1, else enter 0.

$M{n}^{2+}$

Answer 1

Its electronic configuration is:$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4S^{0}3d^5$

$M{n}^{2+}$ is coloured because it has five half-filled 3d orbitals which are responsible for d-d transition.

In order to absorb visible light, an electron would have to move to a higher energy orbital . The difference in energy of the orbitals would have to equal the energy of a visible wavelength photon. For d orbital splitting, the energy difference is right for the visible range.

Hence, answer is $1$.