Question

If the following quadratic equation has two equal and real roots then find the value of k :
$3x^2-18x+k=0$

Answer 1

$3x^2-18x+k=0$

For equal roots, $D=0$

$D=(18{)}^2-4(3)k=0$

$\Rightarrow k=\frac{(18{)}^2}{4\left(3\right)}$

$\Rightarrow k=27$