Question

If the following quadratic equation has two equal and real roots then find the value of k :
$4x^2-5x+k=0$

Answer 1

$4x^2-5x+k=0$

For equal & real roots, $D=0$

$D=(5{)}^2-4(4\left)\right(K)=0$

$\Rightarrow k=\frac{5^2}{4^2}$

$\Rightarrow k=\frac{25}{16}$