You visited us 5 times! Enjoying our articles? Unlock Full Access!

Effect on Kc

If the follow...

Question

If the following reaction has achieved equilibrium in a closed system: $N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)$ . Which of the following is(are) increased by decreasing the size of the container?
I. The value of $K$
II. The concentration of $N_{2} O_{4} (g)$
III. The rate of the reverse reaction

I only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

III only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I and II only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

II and III only

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I, II and III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D II and III only
By decreasing the size of the container, we decrease the volume and hence increase the pressure. The equilibrium will shift to the left-hand side so that there is a decrease in the number of moles of gaseous species.
Hence, the following are increased.
II. The concentration of $N_{2} O_{4} (g)$
III. The rate of the reverse reaction
However, the value of the equilibrium constant $K$ is unaffected.

Suggest Corrections

Similar questions

A + B ⇌ A B + h e a t

A B

A

A B

[C r (N O_{2})_{3} (N H_{3})_{3}]

K_{3} [F e (C_{2} O_{4})_{3}]

[C o C l_{2} (e n)_{2}]^{+}

[C o B r C l (o x)_{2}]^{3 -}

N_{2} O_{4} (g) \to 2 N O_{2} (g)

N_{2} O_{4} (g)

N O_{2}

4.8 \times 10^{- 2}

1.2 \times 10^{- 2}

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g); K_{C} = 4

[N_{2} O_{4}] = [N O_{2}] = 0.1 M

K_{c} = Q

2 N O_{2} (g) \to N_{2} O_{4} (g)

N_{2} O_{4} (g)

2 N O_{2}

N_{2} O_{4} (g)

Join BYJU'S Learning Program