If the following sequence is an arithmetic progression, find its general term. -5, 2, 9, 16, 23, 30, .......... is
A
7n−12
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B
6n−12
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C
5n−12
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D
4n−12
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Solution
The correct option is A7n−12 We can observe the difference between two consecutives terms is equal: 2−(−5)=9−2=16−9=23−16=7
Hence, the sequence is an arithmetic progression with first term a=−5 and common difference d=7. General term of an AP is tn=a+(n−1)d tn=−5+(n−1)×7 tn=7n−12